x^2+0.00000003x+0.000000003=0

Solution for x^2+0.00000003x+0.000000003=0 equation:

x^2+0.00000003x+0.000000003=0

We add all the numbers together, and all the variables

x^2+0.00000003x-9+3.0E=0

We add all the numbers together, and all the variables

x^2+0.00000003x-0.84515451462286=0

a = 1; b = 0.00000003; c = -0.84515451462286;
Δ = b2-4ac
Δ = 0.000000032-4·1·(-0.84515451462286)
Δ = 3.3806180584914
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.00000003)-\sqrt{3.3806180584914}}{2*1}=\frac{-16.154845485377-\sqrt{3.3806180584914}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.00000003)+\sqrt{3.3806180584914}}{2*1}=\frac{-16.154845485377+\sqrt{3.3806180584914}}{2}
$